Надеюсь, что мой почерк будет тебе понятен
Sin²α-1= sin²α-(sin²α+cos²α)= sin²α-sin²α-cos²α= - cos²α
(sinα+cosα)²+(sinα-cosα)²= sin²α+2sinαcosα+cos²α+sin²α-2sinαcosα+cos²α= 2
Tg2a=2tga/(1-tg^2a)=2*49/7*48=7/24
<span>{<span><span>4x−x+2y=1</span><span>3−2x=0,2</span></span></span>
Решение.
Начальные преобразования .
<span><span>{<span><span>4x−x+2y=1</span><span>3−2x=0,2</span></span></span>
</span> <span>{<span><span>3x+2y=1</span><span>−2x+3=0,2</span></span></span><span>
{<span><span>3x+2y=1</span><span>−2x+2,8=0
</span></span></span> Решение методом подстановки.
<span><span>{<span><span>3x+2y=1</span><span>−2x+2,8=0</span></span></span>
</span> <span><span>{<span><span>3x+2y=1</span><span>x=1,4</span></span></span>
</span> <span><span>{<span><span>3<span>(<span>1,4</span>)</span>+2y=1</span><span>x=1,4</span></span></span>
</span> <span><span>{<span><span>2y+3,2=0</span><span>x=1,4</span></span></span>
</span> <span><span>{<span><span>y=−1,6</span><span>x=1,4</span></span></span>
</span> <span>{<span><span>y=−1,6</span><span>x=1,4
</span></span></span> Ответ:
<span><span>(<span><span>75</span>;−<span>85</span></span>)</span>=<span>(<span>1<span>25</span>;−1<span>35</span></span>)</span>≈(1,4;−1,6<span>)</span></span>
Это как весы на одной стороне добро а на другой зло