CaCO3 =t°=> CaO + CO2
масса смеси(CaCO3)= 80 г
w(CaCO3)= 0.8
масса в= 0.8 * 8 = 64 г
Ню(CaCO3)= 64 : (40+12+3*16)=0.64 моль - ню(СО2)
V(CO2)= 0,64 * 22/4= 14.336 литров
Вот решение,сейчас попробую второе решить
CH3-C-O-O-C2H5
название: этилацетат
Fe(NO₃)₃+3CH₃COOH=Fe(CH₃COO)₃+3HNO₃
Fe₃⁺+3NO₃⁻+3CH₃COO⁻+3H⁺=Fe(CH₃COO)₃+3H⁺+3NO₃⁻
Fe₃⁺+3CH₃COO⁻=Fe(CH₃COO)₃
Сa + 2HNO₃ = Ca(NO₃)₂ + H₂↑
Сa + 2H⁺ + 2NO₃⁻ = Ca²⁺ + 2NO₃⁻ + H₂↑
Сa + 2H⁺ = Ca²⁺ + H₂↑
Mg + 2HCl = MgCl₂ + H₂↑
Mg + 2H⁺ + 2Cl⁻ = Mg²⁺ + 2Cl + H₂↑
Mg + 2H⁺ = Mg²⁺ +H₂↑
CaO + 2HCl = CaCl₂ + H₂O<span>
</span>CaO + 2H⁺ + 2Cl⁻ = Ca²⁺ + 2Cl⁻ + H₂O<span>
</span>CaO + 2H⁺ = Ca²⁺ + H₂<span>O
</span>BaO + 2HNO₃ = Ba(NO₃)₂ + H₂O
BaO + 2H⁺ + 2NO₃⁻ = Ba²⁺ + 2NO₃⁻ + H₂O
BaO + 2H⁺ = Ba²⁺ + H₂<span>O
</span>
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O<span>
2</span>H⁺ + SO₄²⁻ + 2Na⁺ + 2OH⁻ = 2Na⁺ + SO₄²⁻ + 2H₂O<span>
2</span>H⁺ + 2OH⁻ = 2H₂<span>O
</span>Mg(OH)₂ + 2HNO₃ = Mg(NO₃)₂ + 2H₂O<span>
</span>Mg(OH)₂ + 2H⁺ + 2NO₃⁻ = Mg²⁺ + 2NO₃⁻ + 2H₂O<span>
</span>Mg(OH)₂ + 2H⁺ = Mg²⁺ + 2H₂<span>O
</span>
<span>BaCl₂ + H₂SO₄ = BaSO₄↓ + 2HCl<span>
</span>Ba²⁺ + 2Cl⁻ + 2H⁺+ SO₄²⁻ = BaSO₄↓ + 2H⁺ + 2Cl⁻<span>
</span>Ba²⁺ + SO₄²⁻ = BaSO₄<span>↓
</span></span>Al(NO₃)₃ + Na₃PO₄ = AlPO₄↓ + 3NaNO₃<span>
</span>Al³⁺ + 3NO₃⁻ + 3Na⁺ + PO₄ = AlPO₄↓ + 3Na⁺ + 3NO₃⁻<span>
</span>Al³⁺ + PO₄ = AlPO₄↓<span> </span>