<span>(xyz)4 =х⁴у⁴z⁴
(-1m)⁶=m⁶</span>
(a^n -b^2m)(-a^n -b^2m) =
-a^2n +b^4m
Ответ
5*(-2/5)-3×(1/3)= -2-1= -3
Cos(4x-2x)>0.5
cos2x>0.5
2πn+π/3 > 2x>-π/3+2πn
π/6+πn> x>-π/6+πn
1)-10x^2 +3x+1=0
d=b^2 - 4ac = 3^2 - 4*(-10)*1 = 9+40 = 49
VD = V49 = 9
-b+ - VD
Xo = ----------------
2a
x1 = -3+9/2 *(-10) = 6/-20 = -3/10
x2 = -3-9/2*(-10) = -12/-20 = 3/5
OTBET: x=-3/10 i x=3/5
2) -3x^2 - 2<em>x</em> +8=0
D = b^2 - 4ac = -2^2 -4*(-3)*8= 4+96 = 100
VD = V100 = 10
x1 = 2+10/2*(-3) = 12/-6 = -2
x2 = 2-10/2*(-3) = -8/-6 = 4/3
3) 3x^2+6+11x=0
3x^2+11x+6=0
D = 11^2 - 4*3*6 = 121 - 72 = 49
VD = V49 = 7
x1 = -6+7/2*3 = 1/6
x2 = -6-7/2*3 = -13/6 = -2 1/6
4) 15+17x-4x^2=0
-4x^2+17x+15 = 0
D = 17^2 - 4*(-4)*15 = 289 +240 = 529
VD = V529 = 23
x1 = -17+23/2*(-4) = 6/-8 = -3/4
x2 = -17-23/2*(-4) = -40/-8 = 5
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