1) a1=5
a2=9
a3=13
a4=17
a5=21
5+9+13+17+21=65
2) a1=10
a2=12
a3=14
a4=16
a5=18
a6=20
a7=22
a8=24
a9=26
a10=28
a11=30
a12=32
a13=34
10+12+14+16+18+20+22+24+26+28+30+32+34=286
3) a1=-18
a2=-22
a3=-26
a4=-30
a5=-34
a6=-38
a7=-42
a8=-46
a9=-50
a10=-54
a11=-58
a12=-62
a13=66
18+22+26+30+34+38+42+46+50+54+58+60+66=-546
<span>f(x)=(4x+1)/(x+3)
u=4x+1 u'=4 v=x+3 v'=1
</span>
f'(x)=1/v²[u'v-v'u]=1/(x+3)²[4<span>(x+3)-1*(4x+1)]=</span>11/(x+3)²
2x-π/3=+-π/4+2πk
2x=+-π/4+2πk+π/3
x=+-π/8+πk+π/6 k∈Z
Ответ:
1) 2a(x^3-(2y)^3)=2a(x-2y)(x^2+x2y+4y^2)
2) 2(4a^4+4a^2+1)=2(2a^2+1)^2
3) (3x)^2-(5a)^2-6x-10a=(3x-5a)(3x+5a)-6x-10a=(3x-5a)(3x+5a)-2(3x+5a)=(3x+5a)(3x-5a-2)
Объяснение: