√(x+5) + √(6-5x-x²)
{x+5≥0
{6-5x-x²≥0
x+5≥0
x≥-5
6-5x-x²≥0
x²+5x-6≤0
x²+5x-6=0
D=25+24=49
x₁=<u>-5-7</u>=-6
2
x₂=<u>-5+7</u>=1
2
+ - +
------- -6 ------------ 1 ------------
\\\\\\\\\\\\\\
x∈[-6; 1]
{x≥-5
{-6≤x≤1
\\\\\\\\\\\\\\\\\\\\\\\\\\\\
-------- -6 ------- -5 ----------- 1 ---------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-5; 1]
-1 и 3
-3-8+11-3=0
81-45-33-3=0
отбросим минусы
и возведем в квадрат
(3+√10)² = 9 + 10 + 6√10 = 19 + 6√10 или 38
6√10 или 19
36 * 10 или 361
360 < 361
3+√10 < √38
-3-10 > -√38
X^2-2x+1=(x-1)^2
(5-1)^2=4^2=16.