580g xg yL
2Ag2O = 4Ag + O2↑
464g 432g 22.4L
x(Ag)=580·432/464=540g
y(O2)=580·22.4/464=28L
<span>2H2C=CH2 + 2[O] (PdCl2+CuCl2) = 2H3C-CHO;
</span>H2C=C=CH2 + H2O (+H+) = H3C-C(O)-CH3;
<span>H3C-CH=CH-CH3 + HCl = H3C-CH(Cl)-CH2-CH3;
</span>H2C=CH-CH2-CH=CH2 + H2 = H2C=CH-CH2-CH2-CH3;
<span>H3C-CH=CH-CH3 + Cl2 = H3C-CH(Cl)-CH(Cl)-CH3.</span>
ответ В
<span> 0 +4</span>
<span>C+2CuO=2Cu+CO2</span>
у простых веществ степень лкисления = 0
в оксиде углерода - +4
Cu2O+O=2CuO..............