6км500м=6500м
6500:5=1300м/мин. - скорость сближения
1300-500=800м/мин. - скорость второго мотоциклиста
(5,75-6 1\7 ) *1 3/11 -2 1/12:(2,28+0,53)
(-11/28)*14/11-25/3*25/281
-1/2-625/843
-843+1250÷1686
Ответ:-2093/1686
Альтернативный вид:
-1 407/1686,≈-1.2414
Периметр квадрата
p=4a
при p=16,4
a=16,4÷4
a=4,1
-1 ≤sinx≤1 ║*(-2)
-2≤-2sinx≤2║+3
1≤-2x+3≤5
Ответ: E (x)=[1 ; 5]
55.
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