- + - +
--------------------[-3]-----------(-2)-----------(2)-----------------
/////////////////////// //////////////
Ответ:
∞
∪
1)3/х+3 + 3/х2-3х + 2х/9-х2=3/х+3 + 3/х(х-3) + 2х/(3-х)(3+х)=3•(х(х-3) + 3•(х+3) -2х•х/х(х+3)(х-3)= 3х2-9х+3х+9-2х2/х(х-3)(х+3)=х2-6х+9/х(х-3)(х+3)=(х-3)2/х(х-3)(х+3)=х-3/х2+3х
3)а^2-b/a-a=0,04+25-0,2=24,84
X (x - 5)(x - 1) = 12(x - 5)
(x - 5) (x(x - 1) - 12) = 0
(x - 5)(x^2 - x - 12) = 0
1) x - 5 = 0
x = 5
2) x^2 - x - 12 = 0
D = 1 + 4*12 = 49
x1 = (1 + 7)/2 = 8/2 = 4
x2 = (1 - 7)/2 = - 6/2 = - 3
Ответ
- 3; 4 ; 5
<span>sqrt{16-t} - \sqrt{3-t} =2
</span>(sqrt{16-t} - sqrt{3-t})(sqrt{16-t} + sqrt{3-t})=2(sqrt{16-t} + sqrt{3-t})
2(sqrt{16-t} + sqrt{3-t})=13
sqrt{16-t} + sqrt{3-t}=13/2