(-27)*(m-y+p)=-27m+27y-27p
18_03_09_Задание № 1:
Вычислите (2−1)(2+1)(2^2+1)(2^4+1)(2^8+1)−2^16
РЕШЕНИЕ: (2−1)(2+1)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^2−1^2)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^2−1)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^4−1^2)(2^4+1)(2^8+1)−2^16=(2^4−1)(2^4+1)(2^8+1)−2^16=(2^8−1^2)(2^8+1)−2^16=(2^8−1)(2^8+1)−2^16=2^16−1^2−2^16=-1
ОТВЕТ: -1
X-y=7 ⇒x=7+y;
xy=5 ⇒(7+y)y=5 ⇒y²+7y-5=0 ⇒
y₁=-7/2+√(49/4+5=-7/2+√69/4=(-7+8.3)/2=0.65
y₂=(-7-8.3)/2=-7.65;
2x^2-x=0+3
2x^2-x=3
2x=3
x=1,5