2Na+2HCL-->2NaCL+H2
2K+S-->K2S
2NaOH+H2SO4-->Na2SO4+2H2O
3Na2O+P2O5-->2Na3PO4
6Na+N2-->2Na3N
2KOH+H2SO4-->K2SO4+2H2O
Масса кислорода 2*32\22,4 = 2,857г
аргона 1*40\22,4 = 1,786г
wAr = 1,786\(1,786 + 2,857) = 0,385
или в % 38,5%
M(Al2O3) = 27 + 27 + 16 + 16 + 16 = 102 г/моль
M(2Al) = 54 г/моль ==> W(Al) = (54/102)*100 = 52.9%
==> W(O) = 100 - 52.9 = 47.1%
<span><span>дано:
Al</span>₂S₃<span>
найти: w(Al), w(S)
решение:
Mr(Al</span>₂S₃<span>) =
27*2 +32*3 = 150
w(э) = Ar(э)*n(э)\Mr(в-ва)
w(Al) = 27*2\150 = 0,36 или 36%
w(S) = 32*3\150 = 0,64 или 64%
ответ:w(S) =64%, w(Al) = 36%,
2Al + 3S = Al</span>₂S₃<span>
<span>2Ar(Al) : 3Ar(S) =2*54 : 3*32 = 108 : 96 =
27 :24</span></span></span>
<span>ну вроде так:</span>
<span>Mg + N2 = Mg3N2 </span>
<span>3H2 + N2 = 2NH3 </span>
<span>6Li + N2 = 2Li3N </span>
<span>2Al + N2 = 2AlN</span>