По теореме Пифагора
b²=c²-a²=10²-8²=100-64=36
b=6
S(Δ)=(1/2)a·b
S(Δ)=(1/2)c·h
⇒
(1/2)a·b=(1/2)c·h
h=a·b/c=8·6/10=4,8
По теореме Пифагора
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1)ax+ay+10x+10y=a(x+y)+10(x+y)=(a+10)(x+y)
2)a²-ab-8a+8b=a(a-b)-8(a-b)=(a-8)(a-b)
3)a²n-anx+x²-ax=an(a-x)-x(a-x)=(an-x)(a-x)
4)5a³c+10a²-6bc-3abc²=5a²(ac+2)-3bc(2+ac)=(5a²-3bc)(ac+2)