CH₃CH₃ C₂H₅
Ι Ι Ι
СH₃-С-СH-С-СH₂-СH₂-СH₂-СH₂-СH₂-СH₃
Ι Ι
Cl C₂H₅
<span><span>2Al</span>+<span>6<span>H2O</span></span>→<span>2<span>AI<span>(OH)</span>3</span></span>+<span>3<span>H2
</span></span></span><span><span>Al<span>(OH)</span>3</span>+<span>3<span>HCl</span></span>→<span>AlCl3</span>+<span>3<span>H2O
</span></span></span><span><span>AlCl3</span>+<span>3<span>H2O</span></span>→<span>Al<span>(OH)</span>3</span>+<span>3<span>HCl
</span></span></span><span><span>Al<span>(OH)</span>3</span>+<span>NaOH</span>→<span>Na<span>[Al<span>(OH)</span>4<span>]
</span></span></span></span>
C+O2=CO2
n=m/M(Ar) M=Ar Ar(C)=12 М=12 г/моль
n(C)=60/12=5моль
n(C) : n(O2)= 1 : 1, след., n(O2)=5моль по условию реакции
V=n*Vm V(O2)= 5*22,4=112л
V(возд.) = 112*100/21=533,3л В воздухе 21\% кислорода
Ответ:533,3л