N(Cl2)=248,5\71=3,5 моль,отсюда v=3,5*22,4=78,4 л
2K+2HCl=2KCL+H2
ню(K)=3.9г/39г/моль=0,1моль
ню(H2)=0.05моль
V(H2)=0.05моль*22.4л/моль=1.12л
V=v(ню)*Vm
Vm=const=22.4 л/моль
v(ню)=m/M=8.8 г/44 г/моль=0,2 моль
V=0,2 моль*22,4 л/моль=4,48 л.
<span><span>2<span>H2O</span></span> → <span>2 <span>H2</span></span>+<span>O2
</span></span><span><span>5<span>O2</span></span>+<span>4P</span> → <span>2<span>P2O5 </span></span></span>
<span><span>P2O5</span>+<span>3<span>H2O</span></span> → <span>2<span>H3PO<span>4
</span></span></span></span>
N2+3H2->2NH3
NH3+HCl->NH4Cl
NH4Cl+HNO3->NH4NO3+HCl
NH4NO3+Q->NH3+HNO3