Zncl2+2NaOH= Zn(oh)2+ 2NaCl
n(ZnCl2)= n(ZnCl2)= m/M=220/(65+35,5*2)=1,6 моль
m( zn(oh)2) n*M= 1,6*99=158,4 г
Изомеры:
СH<span>≡С-СH2-СH2-СH2-СH2-СH2-СH3 октин-1</span>
<span>CH3-CH2-C<span>≡C-CH2-CH2-CH2-CH3 октин-3</span></span>
<span><span>СH2=CH-CH2-CH2-CH=CH-CH2-CH3 октадиен-1,5</span></span>
<span><span>Нитрирование гексана:</span></span>
<span><span>C6H14+HNO3-->(при повышенной температуре,давлении)C6H13NO2+H2O</span></span>
3.2%
Объяснение:
dilute sulfuric acid reacts with zinc to produce hydrogen
zn + h2so4 = znso4 + h2
find the mass of gas released
n (h2) = n (zn) = m (zn) / mr (zn) = 13/65 = 0.2 mol
then the mass of hydrogen m (h2) = n * mr = 0.2 * 2 = 0.4 g
mass of solution at the end of the reaction
m (solution) = m (solution h2so4) + m (zn) - m (h2) = 1000 + 13-0.4 = 1012.6 gr
we put in a mass of zinc sulfate
n (znso4) = n (zn) = 0.2 mol
m (znso4) = n * mr = 0.2 * (65 + 32 + 64) = 32.2 gr
then the mass fraction of sulfate w = m (znso4) * 100% / m (solution) = 32.2 * 100 / 1012.6 = 3.2%