<span><span>4Fe</span>+<span>3<span>O2 </span></span>→ <span>2<span>Fe2O3
</span></span></span><span><span>Fe2O3</span>+<span>6<span>HCl</span></span> → <span>2<span>FeCl3</span></span>+<span>3<span>H2O </span></span></span>
<span><span>FeCl3</span>+<span>3<span>NaOH</span></span> → <span>3<span>NaCl</span></span>+<span>Fe<span>(OH)</span>3
</span></span><span><span>2<span>Fe<span>(OH)</span>3</span></span>+<span>3<span>H2SO4</span></span> → <span>Fe2<span>(SO4)</span>3</span>+<span>6<span>H2<span>O
</span></span></span></span>
Дано:
m(O2) = 62
Найти:
U(O2)
Решение:
1) n(O2) = m/M
n(O2) = 62/32 ~ 1.94 г/моль
2) U(O2) = n x Uм
U(O2) = 1.94 x 22.4 = 43.456 л/моль
Вроде так
2K+2H2O= 2KOH+ H2
Mg+H2SO4=MgSO4+H2
4P+5O2=2P2O5
CaCO3=CaO+CO2
Fe2O3+HCL=FECL3+H2O
BA(NO3)2+K2SO4= BASO4+2KNO3
H2SO4+BACL2=2HCL+BASO4(осадок)
2FE+3CL2(газ)=2FECL3
Как-то так................