Упростили и получили:
x³= (-2)³= -8
(2корня35-корень35+корень31)*(корень35+корень31)/2
Cos10a*cos8a + cos8a*cos6a =
= cos8a * (cos10a + cos6a) =
= cos8a * 2cos (10a+6a)/2* cos(10a-6a)/2 =
= cos8a * 2cos(16a)/2 * cos(4a)/2 =
= cos8a * 2cos8a * cos2a =
= 2cos(2a) * cos^2(8a)