Дано
n(C6H5OH)=1.4mol
------------------------
m(C6H5CL)-?
m(NaOH)-?
C6H5CL+NaOH-->C6H5OH+NaCL
M(C6H5CL)=112.5g/mol
M(NaOH)=40 g/mol
n(C6H5OH)=n(C6H5CL)=n(NaOH) = 1.4 mol
m(C6H5OH)=n*M=1.4*112.5=157.5 g
m(NaOH)=n*M=1.4*40=56 g
ответ 157.5 г - хлорбензола, 56 г - гидроксида натрия.
Na2CO3+2HNO3=2NaNO3+H2O+CO2
FeCl3+3HNO3=Fe(NO3)3+3HCl
<span><span>3<span>Na2S</span></span>+<span>8<span>HNO3=</span></span><span>6<span>NaNO3</span></span>+<span>2<span>NO</span></span>+<span>3S</span>+<span>4<span>H2O
</span></span></span><span><span>3 <span>Na2S</span></span>+<span>2<span>FeCl3=</span></span><span>2<span>FeS</span></span>+S+<span>6<span>NaCl</span></span></span>
SO3+H2O=H2SO4
<span><span>H2SO4</span>+<span>H2O=</span><span>H2OSO4</span> + <span>H2
</span></span>2KI+H2O=K2O+2HI
<span><span>8<span>KI</span></span>+<span>5<span>H2SO4=</span></span><span>4<span>I2</span></span>+<span>4<span>K2SO4</span></span>+<span>H2S</span>+<span>4<span>H2<span>O</span></span></span></span>
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