1/9x+1-1/6x-4/5=2
1/9x-1/6x=2-1+4/5
-1/18x=9/5
x=9/5:(-1/18)
x=32,4
Log₃32*log₂25*log₀,₂3=-10
переход к новому основанию 2.
1. log₃32=log₃2⁵=5*log₃2=5*(log₂2/log₂3)=5*(1/log₂3)=5/log₂3
2. log₂25=log₂5²=2*log₂5
3. log₀,₂3=log₁/₅5=log₂3/log₂(1/5)=log₂3/(log₂5⁻¹)=-log₂3/log₂5
4. (5/log₂3)*(2*log₂5)*(-log₂3/log₂5)=5*2*(-1)=-10
(80с-35):5= 16c-7 Вроде бы правильно...