пусть X - начальное число конфет
6 +(X-6)/3 =X/2
36 +2*X -12=3*X
X=24 конфеты
Y=-5/9×(-3)+2
y=5/3+2
y=2 5/3
<span>log_5 (4x + 5) = 2+ log_5 (x - 4)
</span>log_5 (4x + 5) = log_5 (25) + log_5 (x - 4)
log_5 (4x + 5) = log_5[ (25) * (x - 4)]
4x + 5 = (25) * (x - 4)
4x - 25x = -100 - 5
- 21x = - 105
x = 5
689. 3х-х=-10
2х=-10 |÷2
х=-5
691. 3х-х =-36
2х=-36 |÷2
х=-18
693. 3х+х=24
4х=24 |÷4
х=6
695. 2х +х=9
3х=9|÷3
х=3
697. 5х+х=-24
6х=-24|÷6
х=-4
699. 20х+2х=-110
22х=-110|÷22
х=-5