В ответе четвертого примера можешь дописать = 1/81•30 в 6 степени
2sinxcosx+2cos^2x-2sin^2x-cos^2x-sin^2x=0
2sinx*cosx+cos^2x-3sin^2x=0
-3tg^2x+2tgx+1=0
D=4+4*3*1=16
t=(-2+4)/-6=-1/3
t=(-2-4)/-6=1
tgx=(-1/3) tgx=1
x=-arctg1/3+pik x=pi/4+pin
<span>1)
(2а-11)(11+2а)-(2а-5)</span>² <span>= 0
</span>(2а-11)(2а+11)-(2а-5)²<span>=0
(2а)</span>² - 11² - [(2а)²- 2·2a·5 + 5²] = 0
4a² - 121 - (4a² - 20a + 25) = 0
4a² - 121 - 4a² + 20a - 25 = 0
20a - 146 = 0
20a = 146
a = 146 : 20
a = 7,3
2)
(3х-8у)² = (3x)² - 2·3x·8y + (8y)² = 9x² - 48xy + 64y²
<span>3)
(3,5t-4k)</span>² = (3,5t)² - 2·3,5t·4k + (4k)² = 12,25t² - 28kt + 16k²
Cos(a+b)= cosa.cosb-sina.sinb,
cos2a = cos kv a- sin kv a
sin2b = 2.sinb . cosb.
Nado znat sinb a cos a.
sin kv b = 1- cos kv b = 1-9/25=16/25, sinb = 4/5
cos kv a = 1-sin kv a = 1-64/289 = 225/289, cos a = 15/17
cos(a+b)=15/17.3/5 - 8/17.4/5 =
cos 2a = 225/289 - 64/289 = 161/289
sin2b = 2. 4/5.3/5 = 24/25