4xy−24x−4y+24 = 4(ху - у - 6х+6) = 4(у-6)(х-1)
<span>2)x(16x^2-y^2)=x(4x-y)(4x+y)</span>
S=b₁/(1-q)=14/(1-(-1/6)=14/(7/6)=12
13х + 9y = 17
12x + 2y = 26
Решение
2( 6х + y ) = 2•13
y = 13 - 6x
13x + 9( 13 - 6x ) = 17
13x + 117 - 54x = 17
- 41x = - 100
x = 100/41 = 2 18/41
y = 13 - 6•( 100/41 ) = 13 - ( 600/41 ) = 13 - 14 26/41 ) = - 1 26/41
Ответ ( 2 18/41 ; - 1 26/41 )