<span>K</span><span>HSO</span>₃<span> + KOH = К</span>₂<span>SO</span>₃<span> + H</span>₂<span>O
</span>K⁺ + HSO₃⁻ + K⁺ + OH⁻ = 2К⁺ + SO3²⁻ + H₂O
HSO₃⁻ + OH⁻ = SO₃²⁻ + H₂O
<span>Fe</span>₂<span>(SO</span>₄<span>)</span>₃<span> + 3(NH</span>₄<span>)</span>₂<span>S = Fe</span>₂<span>S</span>₃<span> + 3(NH</span>₄<span>)</span>₂<span>SO</span>₄<span>
</span>2Fe³⁺ + 3SO₄²⁻ + 6NH₄⁺ + 3S²⁻ = Fe₂S₃ + 6NH₄⁺ + 3SO₄²⁻
2Fe³⁺ + 3S²⁻ = Fe₂S₃
<span>2KBeO да да вроде такое </span>
1)6,98 % массовая доля хлорида калия в растворе
<span>30г/430г=0,06976.</span>
Mr (n2o5) = 28+ 80= 108
w (N)= 28:108 = 0,26 or 26\%
С фенолом реагирует <span>Na</span>)