Х+(1\х)=8
(х+(1\х))²=х²+2·х·1\х+(1\х)²=((х²+(1\х)²)+2=8+2=10
1,7*(х-1,2)= 3,2*(х-3,45)
1,7х-2,04=3,2х-11,04
1,7х-3,2х=-11,04+2,04
-15,х= -9
х=6
( 0,4 m + 1)(0,16m^2 - 0,4m + 1)
<span>x /: х-2 + 8 /(2-x)(2+x) - 1/: х+2 = 0</span>
<span>x(2+x)-8-(x-2)=0 x/=-2 x/=2</span>
<span>x^2+x-6=0</span>
<span>x1=-3</span>
<span>x2=2 не подходит</span>
12^(2k-2)/22^(2k-2)6^(2k-3)=2^(2k-2)6^(2k-2)*6/11^(2k-2)2^(2k-2)6^(2k-2)=6/11^(2k-2)