<span>Fe2O3+3H2SO4-->Fe2(SO4)3+3H2O</span>
FeS,SO2,NaHSO3,Na2SO4,NaNO3,O3,So2,Ca(HSO3)2
(NH4)2SO4 + BaCl2 = 2NH4Cl + BaSO4!
2Cu + O2 = 2CuO
ищем ню Cu
<span>V (Cu) = 6,4г : 64г / моль = 0.1 моль </span>
<span>V (Cu) =V (CuO) </span>
<span>m ( CuO ) = 0.1 моль • (64 + 16) = 8 г </span>
Массовая доля фосфора равна 62/142*100%=43.66%
3) 43,7%