<span><span>CuO</span>+<span>H2</span> → Cu + <span>H2O
</span></span><span><span>ZnO</span>+<span>H2</span> → Zn +<span>H2O
</span></span><span><span>HgO</span>+<span>H2</span> → <span>Hg</span>+<span>H2<span>O
</span></span></span>
Гідроксид - іони OH- (зверху - )
<span>Дано:</span>
<span>w (Cl) =
77,5\%</span>
<span>Найти: РxCly</span>
Решение:
<span>n
(э) = w(э) \Ar(э)
</span><span>n(Р<span>) = 100\% - w(Cl) = 100\% - 77,5\% = 22,5\%</span></span>
n (Cl) =
77,5\% \35,5 = 2,2
<span>n (Р) = 22,5\% \31 = 0,73</span>
<span>n (Р) : n (Cl) = 0,7:2,2 = 1:3 = РxCly = Р1Cl3</span>
<span>ответ: Р1Cl3</span>