Только второй номер .......
(-0.6+5.8) · 10
Если надо решить, то:
(-0.6+5.8) · 10 = 5.2 · 10 = 52
А-2, б-4 в-3 так получается
Найдем первый член прогрессии:<span> A</span>1<span> = A</span>k/qk-1
A1<span> = (-16) / (2)</span>4-1<span> = -2</span>
Найдем n-ый член прогрессии:<span> A</span>n<span> = A</span>1·q<span> n - 1</span>
A6<span> = (-2)·(2)</span>6-1<span> = -64</span>
Сумма первых n членов прогрессии:<span> S</span>n<span> = A</span>1·(qn- 1)/(q - 1)
S6<span> = -2·(2</span>6- 1)/(2 - 1) = -126
<span>Первые 10 членов прогрессии: </span>
A1<span> = -2</span>
A2<span> = A</span>1·q = -4
A3<span> = A</span>1·q2<span> = -8</span>
A4<span> = A</span>1·q3<span> = -16</span>
A5<span> = A</span>1·q4<span> = -32</span>
A6<span> = A</span>1·q5<span> = -64</span>
A7<span> = A</span>1·q6<span> = -128</span>
A8<span> = A</span>1·q7<span> = -256</span>
A9<span> = A</span>1·q8<span> = -512</span>
A10<span> = A</span>1·q9<span> = -1024</span>