<span>1.<u>lim(x^2-3x)/(x^2-8)</u> = </span>lim(1-3/x)/(1-8<span><span>/x^2)</span>=1
x-->∞ </span><span>x-->∞
2.<u>lim (x-2)/(√(x+2)-2)</u></span> = lim (x-2)(√(x+2)+2)/(√(x+2)-2)(√(x+2)+2) =
x-->2 x-->2
=lim (x-2)(√(x+2)+2)/(x-2) = lim (√(x+2)+2) =√(2+2)+2=√4+2=4
x-->2 x-->2
2 5/9x*1 9/19=4 2/13*2 8/9
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