Х²<span>+x</span>³<span>=x</span>³<span>+x</span>⁴,
х²=х⁴,
х²-х⁴=0,
х²(1-х²)=0,
х²(1-х)(1+х)=0,
х²=0, 1-х=0, 1+х=0,
х=0. х=1. х=-1.
Ответ: -1; 0; 1.
(x-1)/(2x-1) <1
[(x-1)/(2x-1)] -1<0
[(x-1-2x+1)]/(2x-1)<0
-x/(2x-1) <0
x/(2x-1)>0
____+____(0)____-____(1/2)___+______
x e (-беск.; 0) U (1/2;+беск.)
(3a-2b)^3 + (3a+2b)^3=
=27a^3-54a^2b+36ab^2-8b^3+27a^3+54a^2b+36ab^2+8b^3=
=54a^3+72ab^2=18a(3a^2+4b^2)