3x - 6 => 3(x - 2)
3x - 30m + 1 => 3(x - 10m) + 1
-10 - 30m => -10(1 + 3m)
21mn + 7n => 7n(3m + 1)
x^2 - 2x => x(x - 2)
Наверно:
(x² +2,5x -18)/(1,5x-6) >1;
(x² +2,5x -18)/(1,5x-6) -1>0
((x² +2,5x -18) -(1,5x-6))/ (1,5x-6)>0 ;
(x² -x-12)/ 1,5(x-4))>0
(x - 4)(x+3)/ 1,5(x-4))>0 * * * x-4≠ 0 ⇔x≠4 * * *
(x+3)/1,5)>0 ;
x+3>0 ;
x >- 3 .
ответ : x∈( -3;∞).