N2O5 + 2KOH = 2KNO3+H2O
N2O3 + H2O<span> = 2HNO2
</span><span>2Ca(OH)2 + 4NO2 = Ca(NO3)2 + Ca(NO2)2 + 2H2O
</span><span>4 NH₃+3O₂=2N₂+6H₂O</span>
1)NH3+H2SO4=<span>(NH4)2SO4 </span>
дано
n(CaCL2) = 0.3 mol
--------------------------------
m(CaCO3)-?
CaCL2+Na2CO3-->2NaCL+CaCO3↓
n(CaCL2) = n(CaCO3) = 0.3 mol
M(CaCO3) = 100 g/mol
m(CaCO3) = n*M = 0.3*100 = 30 g
ответ 30 г
дано
n(NaCL) = 0.8 mol
-------------------------------
m(Na2CO3) -?
CaCL2+Na2CO3--->2NaCL+CaCO3
n(Na2CO3) = n(NaCL) / 2 = 0.8 / 2 = 0.4 mol
M(Na2CO3) = 106 g/mol
m(Na2CO3) = n*M = 0.4 * 106
m(Na2CO3) = 42.4 g
ответ 42.4 г
D(N2)=0.572
M(X)=49 г/моль
углеводородов такой молярки нету, ближайший - СH3-CH2-CH3
<span>СН3СООН + С2Н5ОН = CH3COOC2H5 + Н2О</span>
<span>n(C2H5OH) = m(C2H5OH)/M(C2H5OH) = 69/46 = 1,5 моль</span>
<span>m(CH3COOC2H5) = n(CH3COOC2H5)*M(CH3COOC2H5) = 1,5*76 = 114 г.</span>