<span>y=sin(x/8)sin((x/8)-π/2)</span>
<span>y=-sin(x/8)cos(x/8)</span>
<span>y=-0.5*2*sin(x/8)cos(x/8)</span>
<span>y=-0.5*sin(x/4)</span>
<span>поскольку период функции y=sinx равен 2π,то период функции y=-0.5*sin(x/4)</span>
<span>равен 2π/(1/4)=8π</span>
<span>Ответ :8π</span>
5 ^ 7х - 1 = 1
5 ^ 7х - 1 = 5 ^ 0
7х - 1 = 0
7х = 1
Х = 1/7