Первое:
<span><span>2</span><span>Na</span><span>O</span><span>H</span></span><span> + </span><span><span>H</span><span>2</span><span>S</span><span>O</span><span>4</span></span><span> = </span><span>Na</span><span>2</span><span>S</span><span>O</span><span>4</span><span> + </span><span>2</span><span>H</span><span>2</span><span>O</span>
<span><span>2</span><span>Na</span>+<span> + </span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> = </span><span>2</span><span>Na</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> + </span><span>2</span><span>H</span><span>2</span><span>O</span></span>
<span><span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> = </span><span>2</span><span>H</span><span>2</span><span>O</span></span></span>
<span><span><span>Второе:</span></span></span>
<span><span><span>HNO3 + K2CO3 = HK2 + CO3NO3</span></span></span>
<span><span><span><span>HNO</span>3<span> + K</span>2<span>CO</span>3<span> = HK</span>2<span> + CO</span>3<span>NO</span>3</span></span></span>
Третье:
2HCl+MgО=MgCL2+H2O
2H(+)+2Cl(-)+MgО=Mg(+2)+2CL(-)+H2O
2H(+)+MgО=Mg(+2)+H2O
Четвёртое:
<span><span>3</span><span>K</span><span>O</span><span>H</span></span><span> + </span><span><span>Fe</span>(<span>N</span><span>O</span><span>3</span>)<span>3</span></span><span> = </span><span>3</span><span>K</span><span>N</span><span>O</span><span>3</span><span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span>
<span><span>3</span><span>K</span>+<span> + </span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> + </span><span>3</span><span>N</span><span>O</span><span>3</span>−<span> = </span><span>3</span><span>K</span>+<span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+ </span><span>3</span><span>N</span><span>O</span><span>3</span>−</span>
<span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> = </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+</span></span>
Пятое хз каак..
Шестое:
ZnSO4 +K3PO4=ZnSO4<span> +KOH</span>
Это будет Б, В и Д, потому что там кратные связи
<span>Масса чистого железа в чугуне: </span>
<span>m(Fe) = 1*93/100 = 0,93 т </span>
<span>Необходимая масса железной руды: </span>
<span>m(FeO) = 100*0,93/9 = 31 т </span>
<span>Или через пропорции: </span>
<span>m(Fe) - 93\% </span>
<span>1 - 100\% </span>
<span>m(Fe) = 1*93/100 = 0,93 т </span>
<span>m(FeO) - 100\% </span>
<span>0,93 - 9\% </span>
<span>m(FeO) = 100*0,93/9 = 31 т</span>
Na2SiO3 + CuSO4 = CuSiO3↓ + Na2SO4