1) 2Ba+O2=2BaO
2) BaO+H2O=Ba(OH)2
3) Ba(OH)2+2NaCl=BaCl2+2NaOH
<span>m(соли)
= m(р-ра) ∙ w</span>
<span>ж) m(K2CO3) = 140 г ∙ 0,1 = 14 г</span>
<span>в) m(NaCl) = 300 г ∙ 0,05 = 15 г</span>
<span>д) 5% = 0,05 \ m(KCl) = 80 г ∙ 0,05 = 4 г</span>
<span>а) m(NaCl) = 200 г ∙ 0,1 = 20 г</span>
1.Ch2=ch-ch3 + h2o => ch3-ch(oh)-ch3
2. Ch3-ch(oh)-ch3 + hcl => ch3-ch(Cl)-ch3 + h2o
3. Ch3-ch(Cl)-ch3 + koh(водн раствор) => kcl + ch3-ch(oh) -ch3
BaCl2+Na2SO4=BaSO4+2NaCl
U(BaCl2)=2,4г/208.2=0,11 моль.U(BaCl2)=U(BaSO4)=0,11 моль.
m(BaSO4)=0,11*/233.39==2.68г