Дано
m(P) = 31 g
---------------------
V(O2)-?
4P+5O2-->2P2O5
M(P) = 31 g/mol
n(P) = m/M = 31/31 = 1 mol
4n(P) = 5(O2)
n(O2) = 5*1 / 4 = 1.25 mol
V(O2) = n*Vm = 1.25 * 22.4 = 28 L
ответ 28 л
C H3- CH2 - CH(CH3) - CH3 C5H12
C H3- CH(CH3) - C H= C(CH3) - CH2 - CH3 C8H16
C H3- C(CH3)2 - CH2-OH C5H12O
<span>С12Н22О11+Н2О= 2С6Н12О6
вот уравнение</span>