119
119 / 2 = 59, ост. 1
119 / 3 = 39, ост. 2
119 / 4 = 29, ост. 3
119 / 5 = 23, ост. 4
119 / 6 = 19, ост. 5
119 / 7 = 17
77+5 1/3=76 3/3+5 1/3=81 4/3=82 1/3
F(xo+Δx) ≈ f(xo) + d[f(xo)] = f(xo) + f '(xo)*Δx.
1,006 = 1 + 0,006.
<span>f(xo) = 1.
</span>f '(xo) = (√x)' = (x^(1/2))' = (1/2)*x^(-1/2) = 1/(2x²).
<span> f '(1) = 1/2.
</span>
Получаем:
f(xo+Δx) ≈ 1 + (1/2)*0,006 ≈<span> 1,003.
</span>
Точное значение √1,006 = <span><span>1.002996.</span></span>
6 3/7:1 6/7=4,5:у
45/7*7/13=4 1/2:у
45/13=4 1/2:у
у=4 1/2:45/13
у=9/2*13/45
у=13/10=1 3/10
проверка
6 3/7:1 6/7=4,5:1 3/10
45/7*7/13=9/2*10/13
45/13=45/13
3 6/13=3 6/13