CaO+2HNO3=Ca(NO3)2+H2O
n(CaO)=2,8/56=0,05 моль
n(CaO)=n(H2O)
N=Na*n=6,022*10^23*0,05=0,3011*10^23 молекул
FeCl3 = Fe(3+) + 3Cl(-)
Fe(NO3)3 = Fe(3+) + 3NO3(-)
Fe2(SO4)3 = 2Fe(3+) + 3SO4(2-)
Cu(II)O(II), Fe(II)O(II), Fe2(III)O3(II), Mn2(VII)O7(II), Mn(IV)O2(II).
дано
m(Ca) = 180 g
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m(CaOH)2-?
Ca+2HOH-->Ca(OH)2+H2
M(Ca) = 40g/mol
n(Ca) = m/M = 180 / 40 = 4.5 mol
n(Ca) = n(Ca(OH)2) = 4.5 mol
M(Ca(OH)2) = 74 g/mol
m(Ca(OH)2) = n*M = 4.5 * 74 = 333g
ответ 333 г
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