Смотри вложение.........................................................
5х-5=0
5х=5
х=1
при х =1, у=0
при х=0, у=-5
1) 4/(x²+4x+4)=4/(x+2)².
2) (x²+12)/(x²-4)-(x+2)/(x-2)=(x²+12)/((x-2)(x+2))-(x+2)/(x-2)=
=(x²+12-(x+2)²)/((x+2)(x-2))=(x²+12-x²-4x-4)/((x+2)(x-2))=(-4x-8)/((x+2)(x-2))=
=-4*(x-2)/((x+2)(x-2))=-4/(x+2).
3) (4/(x+2)²):(-4/(x+2))=4*(x+2)/(-4*(x+2)²)=-1/(x+2)=-1/(-1+2)=-1/1=-1.
У=0,4х
2х+1,2х=5
3,2х=5
х=50/32=25/16
у=2/5 * 25/16=5/8
Ответ: 25/16 , 5/8