2Cu+4Cl+4Na+4OH= 2Cu(OH)2 +4Na+4Cl
2Cu + 4 OH=2Cu(OH)2
P2O5+3H2O=2H3PO4
1. m (H3PO4) 42.6/142=x/98*2 x=58.5
2. m H2O на реакцию 42,6/142=у/3*18 у=16,2
3. m H2O оставшейся = 200-16,2=183,8
4. м раствора= 58,5+183,8=242,3
5. W = 58.5*100/242.3=24.14%
Zn+2HCl->ZnCl2+H2
130-x
65-22.4
x=130*22.4/65=44.8
M(C5H11O2N) = 117 г/моль
м.д. (С) = 60/117*100 = 51,28%
м.д. (N) = 14/117*100 = 11,96%
м.д. (О) = 32/117*100 = 27,35%
2C2H5OH=CH2=CH-CH-CH2+H2+2H2O
n(C2H6O)=100 :46=2,17моль-избыток!
n(C4H6)=3<36:22,4=0,15моль;
n(C2H6O)=0,15*2=0,3моль; m(C2H6O)=0,3*46=13,8г;
W(C2H6O)=13,8:100=0,138(13,8%).
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