1) = BaSO4+H2
а вторая реакция по идеи, не пойдет
Значение органической химии
C + 2H2 = CH4
CH4 + Br2 = CH3Br + HBr
2CH3Br + 2Na = CH3-CH3 + 2NaBr
CH3-CH3 + Cl2 = CH3-CH2Cl + HCl
2CH3-CH2Cl + 2Na = CH3-CH2-CH2-CH3 + 2NaCl
CH3-CH2-CH2-CH3 =(t)= CH3-CH3 + CH2=CH2
2CH3-CH3 + 7O2 = 4CO2 + 6H2O
Дано
V(CH4) = 56 дм3
Решение
n(CH4) = V(CH4) / Vm = 56 / 22.4 = 2.5 моль
N(CH4) = n(CH4) * Na = 2.5 * 6.02 * 10^23 = 15.05 * 10^23 = 1.505 * 10^24
N(C) = 1N(CH4) = 1 * 1.505 * 10^24 = 1.505 * 10^24
N(H) = 4N(CH4) = 4 * 1.505 * 10^24 = 6.02 * 10^24
Ответ:
N(C) = 1.505 * 10^24
N(H) = 6.02 * 10^24