M1(в-ва)=200*10/100=20г
m(р-ра)= 200+50=250
w=(20/250)*100%=8%
M(CaCl2) = 500 r*0.2 = 100 r
А) m"(p.CaCl2) = 500 r+100 r = 600 r
ω"(CaCl2) = 100 r/600 r = 0,1667 або 16,67%
Б)
m"(p. CaCl2) = 500 r + 100 r = 600 r
m"(CaCl2) = 100 r + 100 r = 200 r
ω"(CaCl2) = 200 r/600 r = 0,3333 або 33,33%
N : 1s2 2s2 2p3
P : 1s2 2s2 2p6 3s2 3p3