<span>12-(4-x)²=x(3-x)
12-16+8х-</span> x^{2} =3х- x^{2}
8х-3х+ x^{2} - x^{2} =16-12
5х=4
4
х=⁻⁻⁻
5
х=0,8
Ответ: 0,8
f`(x)=-6x²+6x+12
-6(x²-x-2)=0
x1+x2=1 U x1*x2=-2
x1=-1 ∈[-2;1] U x2=2∉[-2;1]
y(-2)=16+12-24+5=9
f(-1)=2+3-12+5=-1 наим
f(1)=-2+3+12+5=18 наиб
P - Q = (1/3х - 1/3y) - (x+2y) - (1/3x + 1/3y - (x-y)) =
= 1/3x-1/3y -x -2y -1/3x -1/3y +x -y = x*(1/3-1-1/3+1) - y(1/3+2+1/3+1)=
= -3 2/3 y
!!!!!!!!!!!!!!!!!!!!!!!!!!
<span>-3x+6=0 решите))))))))))))))))))</span>