Так как А =0.6 + В ;А больше В
<span>а)d=(An-Ak)/(n-k)</span>
<span>d=-1,7/17=0,1</span>
б)An=A1+(n-1)*d
Пусть A1=x
270=x+10*(-3)
x=300
т.е. А1=300
А100=300+99*(-3)
А100=3
(9 -2√3)/(3√6 -2√2) =√3(<u>3√3 -2</u>)/√2(<u>3√3 -2</u>) =√(3/2).
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(2√2 -x√x) / (2 +√(2x) +x) =((√2)³ -(√x)³ ) / (2 +√(2x) +x) =
(√2 -√x) (<u>2 +√(2x) +x</u>) / (<u>2 +√(2x) +x</u>) = √2 -√x .
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(a -√(3a) +3)/(a√a+3√3) = (a -√(3a) +3)/((√a)³+(√3)³) =(<u>a -√(3a) +3</u>)/(√a+√3)(<u>a -√(3a) +3</u>) =
1/(√a+√3).
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(2√10 - 5)/(4 -√10) =2(2√10 -5)/2(4 -√10) =(4√10 -10)/2(4 -√10) =√10(<u>4 -√10</u>)/2(4 -√10) =
(√10)/2.
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((√10 -1)² -3)/(√10 +√3 -1) =((√10 -1)² -(√3)²)/(√10 +√3 -1) =
=(√10 -1 -√3)(<u>√10 -1 +√3</u>)/(<u>√10 +√3 -1</u>) = √10 -1 -√3.
Log₆(x+3)(x-2) = log₆6
(x+3)(x-2) = 6
x² - 2x +3x - 6 = 6
x² + x - 12 = 0
x₁ = 3
x₂ = - 4