Sin(45° + α) - cos(45° + α) / sin(45° + α) + cos(45° + α) = (√2/2•cos α + √2/2•sin α - (√2/2•cos α - √2/2•sin α)) / (√2/2•cos α + √2/2•sin α + (√2/2•cos α - √2/2•sin α)) = √2•sin α / √2•cos α = tg α
<span>2sin²x=3√2 sin(П/2-x)+4
2-2cos</span>²x=3√2cosx+4
2cos²x+3√2cosx+2=0
cosx=t
2t²+3√2t+2=0
D=(3√2)²-4*2*2=18-16=2
t1=(-3√2-√2)/4=-4√2/4=-√2⇒cosx=-нет решения
t2=(-3√2+√2)/4=-2√2/4=-√2/2⇒cosx=-√2/⇒x=-3π/4+2πk U x=3π/4+2πk,k∈z
А) если там 2х, то а=2, б=0, с=2
Б)а=1, б=3, с=0
В)а=2, б=0, с =4,5
Г)а=-3, б=1, с=0