X+y+z=5
x-y+z=1
x+z=3
_____________
x=3-z
y=x+1
3-z+x+1+z=5
_____________
решаем нижнее, получаем х=1
Подставляем и получаем:
x=1
y=2
z=2
<span>y`=2cosx-2cosx+2x*sinx-x=0
2x*sinx-x=0
x(2sinx-1)=0
x=0
sinx=1/2⇒x=π/6
y(0)=2sin0-2*0*cos0-0,5*0=0 -наиб
y(π/6)=2sinπ/6-2*π/6*cosπ/6-0,5*π²/36=1-π/3*√3/2-π²/72≈1-0,89-0,14≈-0,03</span>
Π(8х +6)/9 = +-arcCos(-1/2) + 2πk, k∈Z
π(8х +6)/9 = +- 2π/3 + 2πk, k∈Z
(8x + 6)/9 = +- 2/3 + 2k, k∈Z
8x + 6 = +-6 + 18k, k ∈Z
8x = -6 +-6 + 18k, k ∈Z
x = -3/4 +-3/4 + 4,5k, k∈Z
1) k = 0 3)k = 0
x = -3/4 +3/4= 0 x = -3/4 -3/4 = -6/4 = -1,5
2) k = 1 4) k = 1
x = -3/4 + 3/4 + 1= 1 x = -3/4 -3/4 +1 =<span> -0,5</span>
1. Значення функции у=-2*2+5
у=1
2.-1=-2х+5
2х=1-5
х=-2