См=моли делить на объм в мл.отсюда=0.18 моль хлорида натрия.
0.18 умножаем на 58.5=10.53 г хлорида натрия
1. HCOOH+NaOH=HCOONa+H2O
2.H2SO4+2KOH= K2SO4+2H2O
4. щелочной гидролиз
СH3COOC2H5+NaOH=CH3COONa+C2H5OH
Cu+FeCl2=<span>Fe+CuCl2</span>
<span><span>2</span>Na<span> +2</span>H2O<span>=2NaOH+</span>H2</span>
1)
2Cu + O2<span> → 2CuO (нагревание)</span>
CuO + 2HCl → CuCl2<span> + H</span>2O
CuCl2<span> + 2NaOH → Cu(OH)</span>2↓ + 2NaCl
Cu(OH)2<span> → CuO + H</span>2O (нагревание)
CuO + H2SO4<span> → CuSO</span>4<span> + H</span>2O
2)
AlCl3<span> + 3NaOH → Al(OH)</span>3↓ + 3NaCl
2Al(OH)3<span> → Al</span>2O3<span> + 3H</span>2O (нагревание)
Al2O3<span> + 3H</span>2SO4<span> → Al</span>2(SO4)3<span> + 3H</span>2O
Al2(SO4)3<span> + 6KOH → 2Al(OH)</span>3↓ + 3K2SO4
Al(OH)3<span> + HCl → Al(OH)</span>2Cl + H2O
3)
Na2O + H2O → 2NaOH
NaOH + H2SO4<span> → NaHSO</span>4<span> + H</span>2O
2NaHSO4<span> → Na</span>2SO4<span> + H</span>2O + SO3<span>↑ (нагревание)</span>
Ответ: г) золото...........