<span>a) 4NH3+7O2=4NO2+6H2O</span>
<span>N+3 -1e- => N+4 1</span>
<span>O2 +2*2e- => 2O2- 4</span>
<span><span>b)2Al+3i2=2Ali3</span></span>
<span><span>Al -3e- => Al3+ 2</span></span>
i2 +2*1e- => 2i- 3
<span> c)5HNO3+3P+2H2O=3H3PO4+5NO </span>
N+5 +3e- => N+2 5
P -5e- => P+5 3
<span>d)<span>2</span><em>K</em><em>Mn</em><em>O</em>4<span> + </span><span>16</span><em>H</em><em>Cl</em><span> = </span><span>5</span><em>Cl</em>2<span> + </span><span>2</span><em>K</em><em>Cl</em><span> + </span><span>2</span><em>Mn</em><em>Cl</em>2<span> + </span><span>8</span><em>H</em>2<em>O</em></span>
<em>Mn+7 +5e- =>Mn+2 2</em>
<em>2Cl- -1*2e- =>Cl2 5</em>
Mr(NaOH) = 23 + 16 + 1 = 40
W(Na) = Ar(Na) * n / Mr(NaOH) *100% = 23 / 40 * 100% = 57,5
W(O) = Ar(O) * n / Mr(NaOH) *100% = 16 / 40 *100% = 40%
W(H) = Ar(H) *n / Mr(NaOH) *100% = 1 / 40 *100% = 2,5%
Mr(Al2O3) = 27 *2 + 16 *3 = 102
W(Al) = Ar(Al) * n / Mr(Al2O3) *100% =27 *2 / 102 *100% = 53
W(O) = Ar(O) * n / Mr(Al2O3) * 100% = 16 * 3 / 102 *100% = 47%
3-бром-3этилпентан.
Должно быть так.
чсло молекул равно v=N/Na N=Na*v=0,75моль*6,02*10^23моль-1=4,515*10^23