<span>3O2 + 4Al = 2Al2O<span>3
</span></span><span>2NH3 + 2Al = 2AlN + 3H<span>2
</span></span><span>Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O
</span><span>Al2O3 + 6HCl = 2AlCl3 + 3H2O
</span><span>AlCl3 + 3 KOH = Al(OH)3 + 3KCl
</span><span>3H2SO4 + 2Al(OH)3 = Al2(SO4)3 + 6H2O
</span><span>NaOH + Al(OH)3 = NaAlO2 + 2H2O
</span>
<span>O2 + S = SO<span>2
</span></span><span>2SO2 + O2 = 2SO<span>3
</span></span><span>SO3 + H2O = H2SO4
</span>SO2<span> + </span>H2O<span> = </span>H2<span>SO3
</span><span>2KOH + H2SO4 = K2SO4+ 2H2O
</span><span>K2SO4 + Ba(OH)2 = BaSO4 + 2KOH
</span>H2SO3 = SO2 + H2O
<span>2NaOH + SO2 = Na2SO3 + H2O
</span>
<span>4P + 5O2 = 2P2O<span>5
</span></span><span>P2O5 + 3H2O = 2H3PO<span>4
</span></span><span>3KOH + H3PO4 = K3PO4 + 3H2O
</span><span>2K3PO4 + 3CaCl2 = Ca3(PO4)2 + 6KCl
</span><span>3NaOH + H3PO4= Na3PO4 + 3H2O
</span>2H3PO4<span> + </span>Mg<span> = </span>Mg3(PO4)2<span> + 3H2
</span><span>3AgNO3 + H3PO4 = Ag3PO4 + 3HNO<span>3</span></span>
Дано:
m(розчину H2SO4)=300г
w(H2SO4)=9,8%=0,098
V(Н2)-?
знайдемо масу сульфатної кислоти (речовини) в розчині: 300*0,098=29,4г
29,4г Хл
Fe + H2SO4=FeSO4+H2
98г 22,4л
х=29,4*22,4/98=6,72л
Видно должно быть
.................
Ответ:
ответ на фото
к сожалению Г-название спирта не знаю
2Ba+O₂=2BaO
BaO+CO₂=BaCO₃
BaCO₃+2НNO₃=Ba(NO₃)₂+Н₂О+CO₂↑
BaCO₃+2H⁺+2NO₃⁻=Ba²⁺+2NO3⁻+H2O+CO2
BaCO3+2H⁺=Ba²⁺+H2O+CO2
Ba(NO₃)₂+2HCl <=>BaCl₂+2HNO₃
BaCl₂+H₂SO₄=BaSO₄↓+2HCl