Var
b,i:integer;
S:string;
Begin
Readln(S);
b:=0;
For i:=1 to length(s) do
if i<length(s) then begin
if (s[i]='ж') or (s[i]='ш') then if s[i+1]='ы' then begin s[i+1]:='и'; b:=b+1; end;
End;
Writeln(b);
Writeln(s);
<span>End.</span>
5A316 = 3·160+10·161+5·162
= 3·1+10·16+5·256 = 3+160+1280 = 144310
0hex
=
0dec
=
0oct
0
0
0
0
1hex
=
1dec
=
1oct
0
0
0
1
2hex
=
2dec
=
2oct
0
0
1
0
3hex
=
3dec
=
3oct
0
0
1
1
4hex
=
4dec
=
4oct
0
1
0
0
5hex
=
5dec
=
5oct
0
1
0
1
6hex
=
6dec
=
6oct
0
1
1
0
7hex
=
7dec
=
7oct
0
1
1
1
8hex
=
8dec
=
10oct
1
0
0
0
9hex
=
9dec
=
11oct
1
0
0
1
Ahex
=
10dec
=
12oct
1
0
1
0
Bhex
=
11dec
=
13oct
1
0
1
1
Chex
=
12dec
=
14oct
1
1
0
0
Dhex
=
13dec
=
15oct
1
1
0
1
Ehex
=
14dec
=
16oct
1
1
1
0
Fhex
=
15dec
=
17oct
1
1
1
1
Var a, x, b, s: real;
begin
write('a = ');
readln(a);
write('b = ');
readln(b);
if (-2*b)/a < 0 then writeln('Нет решения') else
begin
x:=sqrt((-2*b)/a);
if x=0 then writeln('x = 0') else
writeln('x1 = ', x, ' | x2 = ', -x)end
end.
F(16)=1111(2)
1(16)=0001(2)
0(16)=0000(2)
9(16)=1001(2)
B(16)=1011(2)
1111 0001 0000 1001 1011 1011
делить на тройки надо с правого края
111 100 010 000 100 110 111 011
каждую тройку перевести в десятичное число
111(2)=1*2^0+1*2^1+1*2^2=7(8)
100(2)=4(8)
010(2)=2(8)
000(2)=0(8)
100(2)=4(8)
110(2)=6(8)
111(20=7(8)
011(2)=3(8)
Ответ 74204673(8)
Я думаю,что будет таак
13599---- XIIIDXCIX
и
333988-------CCCXXXIIICMLXXXVIII