Log₂<span> ( x -3 ) > 4 ОДЗ: х - 3 > 0 </span>→ x > 3<span>
</span>log₂ ( x -3 ) > <span>log</span>₂<span> 16
х - 3 > 16
x > 19
Ответ: х </span>∈ (19; +∞)<span>
</span>
X² + x - 10 = x - 1 это система
x - 1 >0
x² - 9 = 0
x > 1
x = 3 или x = - 3
x > 1
x = 3
3x-2y-11=03(<span>2-y</span>)-2y-11=0
6-3y-2y-11=0
-5y-5=0 /:(-5<span>)
y+1=0
y=-1
</span>x=2-y=2-(-1)=3