<span>1) FeO + 2H</span><span>Cl</span><span> = Fe</span><span>Cl₂</span><span> + H</span><span>₂O</span>
<span>FeO + 2H⁺ + 2Cl⁻ = Fe²⁺ + 2Cl⁻ + H₂O</span>
<span>FeO + 2H⁺ = Fe²⁺ + H₂O</span>
<span> </span>
<span>2)Fe</span><span>₂</span><span>O</span><span>₃</span> + 6<span>H</span><span>Cl</span>= 2<span>Fe</span><span>Cl</span><span>₃</span> + 3<span>H</span><span>₂</span><span>O</span>
<span>Fe</span><span>₂</span><span>O</span><span>₃ + 6</span><span>H</span><span>⁺ + 6</span><span>Cl</span><span>⁻ = 2</span><span>Fe</span><span>³⁺ + 6</span><span>Cl</span><span>⁻ + 3</span><span>H</span><span>₂</span><span>O</span>
<span>Fe₂O₃ + 6H⁺ = Fe³⁺ + 3H₂O</span>
Решение на фото.........................
2NaOH + H2SO4 =Na2SO4 + 2H2O
80г щелочи - 142г соли
20г щелочи- х г соли
х= 35.5 г
2Al+3H2SO4=Al2(SO4)3+3H2
Al2(SO4)3+6NaOH=2Al(OH)3+3Na2SO4
2Al(OH)3=Al2O3+3H2O
Al2O3+Na2CO3=2NaAlO2+CO2